Opened 2 years ago
Closed 2 years ago
#7558 closed bug (fixed)
Terrible error message when given and wanted are both insoluble
Reported by: | simonpj | Owned by: | simonpj |
---|---|---|---|
Priority: | normal | Milestone: | 7.8.1 |
Component: | Compiler | Version: | 7.6.1 |
Keywords: | Cc: | ||
Operating System: | Unknown/Multiple | Architecture: | Unknown/Multiple |
Type of failure: | None/Unknown | Test Case: | gadt/T7558 |
Blocked By: | Blocking: | ||
Related Tickets: | Differential Revisions: |
Description
In fixing the ambiguity check I came across this tricky program
data T a b where MkT :: (a~Maybe b) => a -> Maybe b -> T a b f :: T a a -> Bool f (MkT x y) = [x,y] `seq` True
We get an error message
Frozen2.hs:12:18: Could not deduce (a ~ Maybe a) from the context (a ~ Maybe a) bound by a pattern with constructor MkT :: forall a b. a ~ Maybe b => a -> Maybe b -> T a b, in an equation for `f' at Frozen2.hs:12:4-10 `a' is a rigid type variable bound by the type signature for f :: T a a -> Bool at Frozen2.hs:11:6 Relevant bindings include f :: T a a -> Bool (bound at Frozen2.hs:12:1) x :: a (bound at Frozen2.hs:12:8) y :: Maybe a (bound at Frozen2.hs:12:10) In the expression: y In the first argument of `seq', namely `[x, y]' In the expression: [x, y] `seq` True
This error message is nonsense! It arises becuase the "insolubles" get both a "given" insoluble (a~T a) and a "wanted" insoluble with the same type.
This can also arise, rather more easily, with the new ambiguity check, via an inaccessible context
foo :: forall a. (a ~ T a) => a -> a
It's a bit obscure, but it needs fixing.
Change History (3)
comment:1 Changed 2 years ago by igloo
- Milestone set to 7.8.1
- Owner set to simonpj
comment:2 Changed 2 years ago by monoidal
comment:3 Changed 2 years ago by simonpj
- Resolution set to fixed
- Status changed from new to closed
- Test Case set to gadt/T7558
Good point. Thanks.
Simon
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This seems to be fixed in HEAD; can someone verify and possibly add a test?